20x/(x^2-4)^2

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Solution for 20x/(x^2-4)^2 equation: 


D( x )

(x^2-4)^2 = 0

(x^2-4)^2 = 0

(x^2-4)^2 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

(20*x)/((x^2-4)^2) = 0

20*x = 0 // : 20

x = 0

x = 0

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